Favorite Music
Nobody knows… yet…
Favorite Instrument
Guitar
Hardest song I ever mastered
"Blue Sky" by The Allman Brothers Band
Song I can’t stop playing
"Hammer Smashed Face" by Cannibal Corpse
Band that Should be in Rock Band
Rainbow
Song I want played at my graduation / wedding / funeral
Fats Waller - Pretend That There's a Moon
Personal rock hero
J. Morrisson & Sascha Konietzko
DLC Wishlist
Sangreal by Septic Flesh
Recent Pictures
Recent Comments
dinoman...
it's good to see another norwegian on these boards, hei:)
opethian...
I figured out the problem in your sig. It's kind of easy. One of my degrees is in math, so I love this sig. :)
@macamatic: More than plausible. Quite solvable. Yes, it's a true statement (I hated it when one of my professors tricked me into trying to prove something that isn't true).
1.) Find the derivatives of g and h using the product rule.
2.) Divide both sides of both equations by f' (f' is not 0, so it's ok).
3.) Use simple algebra to show that the right hand side of both equations are the same.
4.) Thus, g'/f' = h'/f' which implies that g' = h'.
5.) Abracadabra. QED.
macamatic...
Is your sig actually plausible or were you just trying to see how many people would actually try to figure it out? I found myself trying to prove that 2^(x+1) = 0...
FTM311...
Where is your signature "--Being unique, original and clever is frowned upon...get back in line--" from?
fuselage321...
You are not the nicest person I have met.
Wednesday, November 18, 2009